Magnesium on heating to redness in an atmosphere of $N_{2}$ and then on treating with $H_{2} O$ gives?

N H_{3}

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H_{2}

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N_{2}

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O_{2}

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Solution

The correct option is A $N H_{3}$
Megnesium when heated with $N_{2}$ in atmosphere it forms magnesium nitride( $M g_{3} N_{2}$ ) which on hydrolysis(reaction with water) gives ammonia.
$3 M g + N_{2} \to M g_{3} N_{2}$
$M g_{3} N_{2} + 6 H_{2} O \to 3 M g (O H)_{2} + 2 N H_{3}$ .
Hence option A is correct.

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Similar questions

N_{2} + 3 H_{2} ⇌ 2 N H_{3}; K_{1}

N_{2} + O_{2} ⇌ 2 N O; K_{2}

H_{2} + \frac{1}{2} O_{2} ⇌ H_{2} O; K_{3}

2

N H_{3}

A l_{2} O_{3}

N_{2}

M g_{3} N_{2}

M g_{3} N_{2}

N H_{3}

2 M g + O_{2} \to 2 M g O

3 M g + N_{2} \to M g_{3} N_{2}

M g_{3} N_{2} + 6 H_{2} O \to 3 M g (O H)_{2} + 2 N H_{3} ↑

S T P

H_{2}, N_{2}, O_{2}

H B r

In which of the following equilibria, the value of $K_{P}$ is less than $K_{C}$

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