Magnesium reacts with an element (X) to form an ionic compound. If the ground state electronic configuration of (X) is $1 s^{2}$ $2 s^{2}$ $2 p^{3}$ , the simplest formula for this compound is:

M g_{2} X

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M g X_{2}

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M g_{2} X_{3}

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M g_{3} X_{2}

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Solution

The correct option is D $M g_{3} X_{2}$
Electronic configuration of element X is $1 s^{2}$ $2 s^{2}$ $2 p^{3}$ which shows that the element has a valency of 3 and it belongs to group 15. So the element is Nitrogen ( $N$ ) as the atomic number comes out to be 7 from the electronic configuration,

as the valency of $M g$ is 2, the reaction is:
$3 M g$ + $N_{2}$ $⟶$ $M g_{3} N_{2}$

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Magnesium reacts with an element (X) to form an ionic compound. If the ground state electronic configuration of (X) is 1s2 2s2 2p3, the simplest formula for this compound is:

Magnesium reacts with an element (X) to form an ionic compound. If the ground state electronic configuration of (X) is $1 s^{2}$ $2 s^{2}$ $2 p^{3}$ , the simplest formula for this compound is: