Magnesium reacts with an element $(X)$ to form an ionic compound. If the ground state electronic configuration of $(X)$ is $1 s^{2} 2 s^{2} 2 p^{3}$ , the simplest formula for this compound is :

M g_{2} X

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M g_{2} X_{3}

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M g_{3} X_{2}

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M g X_{2}

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Solution

The correct option is B $M g_{3} X_{2}$
Magnesium is an alkaline earth metal and forms $M g^{2 +}$ ion.

The element $X$ with ground state electronic configuration of $1 s^{2} 2 s^{2} 2 p^{3}$ will form $X^{- 3}$ ion.

The charges on cation and anion will be balanced when 3 $M g^{2 +}$ ions will combine with 2 $X^{- 3}$ ions to form $M g_{3} X_{2}$

Hence, the correct option is C.

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Magnesium reacts with an element (X) to form an ionic compound. If the ground state electronic configuration of (X) is 1s22s22p3, the simplest formula for this compound is :

Magnesium reacts with an element $(X)$ to form an ionic compound. If the ground state electronic configuration of $(X)$ is $1 s^{2} 2 s^{2} 2 p^{3}$ , the simplest formula for this compound is :