Question

Magnetic dipole moment of given star if each side of it is of length a is given as $3n{a}^2$ i, Then n is(up to two decimal places)

Answer 1

Total area of loop is
$A=\frac{\sqrt{3}}{4}{a}^2\times 6+\frac{\sqrt{3}}{4}{a}^2\times 6=3\sqrt{3}{a}^2$
$\mu =iA=3\sqrt{3}{a}^{2}i$