Question

Magnetic field at point 'P' due to finite length wire LN (Where I in ampere and a in meter) is

Answer 1

Magnetic field at point P due to to finite length wire LN

(where $1$ is ampere and a in meter) is

$B=\frac{\mu I\sin \theta dl}{r^2}=\frac{{\mu }_0\times I\sin 90°\times \left(\frac{25a}{12}\right)}{(\frac{3a}{4}{)}^2}=\frac{{\mu }_{0}I\times 25a\times 16}{12\times 2a^2}=\frac{100{\mu }_{0}I}{9a}$