Question

Magnetic field of light ray is given by $\overrightarrow{B}=(3\hat{i}+4\hat{j})\times {10}^{-4}sin(kz+\omega t)$ & electric field is given by $\overrightarrow{E}=(\alpha \hat{i}+\beta \hat{j})\times {10}^{4}sin(kz+\omega t)$, then what is the relation between $\alpha \&\beta$

• A. $\alpha =\beta$
• B. $\frac{\alpha }{\beta }=-\frac{4}{3}$
• C. $\frac{\alpha }{\beta }=2$
• D. $\frac{\alpha }{\beta }=\frac{4}{3}$

Answer 1

The correct option is B $\frac{\alpha }{\beta }=-\frac{4}{3}$

$\overrightarrow{E}.\overrightarrow{B}=0$