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Question

Magnetic flux in a circular coil of resistance 10Ω changes with the time as shown in the figure. Magnetic field direction is perpendicular to paper inwards. Match the following:

Table 1 Table 2
(a) At 1s is induced current is
(p) clock wise
(b) At 5 s induced current is
(q) anticlockwise
(c) At 9s is induced current is
(r) zero
(d) At 15 s induced current is
(s) 2A
(t) None


22462.png

A
a-q; b-r; c-p; d-q
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B
a-p; b-r; c-q; d-p
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C
a-r; b-p; c-q; d-r
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D
a-p; b-r; c-s; d-q
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Solution

The correct option is A a-q; b-r; c-p; d-q
t=1sec,dΦdt=102=5,i=510=.05A, +ve flux therefore anti clockwise current
t=5s,dΦdt=0,i=0
t=9s,dΦdt=10+10610=5,i=0.5A, i.e. clockwise current
t=15s,dΦdt=102=5,i=0.5A, i.e. anti clockwise
58430_22462_ans.png

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