Question

Magnetic induction on the axial line due to a short bar magnet is $\frac{{\mu }_o}{4\pi }\frac{2M}{d^3}N{(A-m)}^{-1}$.

• A. True
• B. False

Answer 1

The correct option is A True

Magnetic induction $B$ at point p is,

$B=\frac{{\mu }_0}{4\pi }\frac{2md}{{(d^2-l^2)}^2}$ ..(1)

For short bar magnet ${(d^2-l^2)}^2\approx d^4$

Hence (1) becomes,

$B=\frac{{\mu }_0}{4\pi }\frac{2md}{d^4}$