Magnetic moment 2.84 B.M. is given by (At. nos. Ni = 28, Ti = 22, Cr = 24, Co = 27)
A
Cr2+
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B
Co2+
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C
Ni2+
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D
Ti3+
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Solution
The correct option is CNi2+ Magnetic moment (μ)=√n(n+2)=2.84B.M , which corresponds to 2 unpaired electrons. Cr2+−3d4, 4 unpaired electrons Co2+−3d7, 3 unpaired electrons Ni2+−3d8, 2 unpaired electrons Ti3+−3d1, 1 unpaired electron