Question

Magnetic moment 2.84 B.M. is given by (At. nos. Ni = 28, Ti = 22, Cr = 24, Co = 27)

• A. $C{r}^{2+}$
• B. $C{o}^{2+}$
• C. $N{i}^{2+}$
• D. $T{i}^{3+}$

Answer 1

The correct option is C $N{i}^{2+}$

Magnetic moment $\left(\mu \right)=\sqrt{n(n+2)}=2.84B.M$ , which corresponds to 2 unpaired electrons.
$C{r}^{2+}-3d^4$, 4 unpaired electrons
$C{o}^{2+}-3d^7$, 3 unpaired electrons
$N{i}^{2+}-3d^8$, 2 unpaired electrons
$T{i}^{3+}-3d^1$, 1 unpaired electron