Magnetic moment due to the motion of the electron in $n^{t h}$ energy state of hydrogen atom is proportional to

$n^{5}$

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$n^{3}$

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$n$

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$n^{0}$

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Solution

The correct option is C
$n$

$\frac{Magnetic moment}{Angular momentum} = \frac{e}{2 m}$

$\Rightarrow$ Magnetic moment $α$ angular momentum

$\Rightarrow M \propto n$ ${∵ L = n \frac{h}{2 π}}$

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The time taken by the electron in one complete revolution in the $n^{t h}$ Bohr's orbit of the hydrogen atom is:

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