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Question

Magnetic moment of [MnCl4]2 is 5.92B.M. Explain giving reason.

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Solution

For the given complex [MnCl4]2, the oxidation state of Mn will be;

x+4(1)=2

x=2+4=+2

Thus, oxidation state of Mn is +2.

Electronic configuration of
Mn2+=[Ar]3d54s0

In the given complex , Cl is a weak field ligand thus it does not cause pairing of electrons.


Thus, [MnCl4]2 has 5 unpaired electrons.

Now, magnetic moment is calculated by the formula:

μ=n(n+2)

where n = number of unpaired electrons

𝜇 = √(5(5+2)) = √(35 ) = 5.92 𝐵.𝑀.

So, magnetic moment of [MnCl4]2 is 5.92BM. due to the presence of 5 unpaired electrons.


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