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Multi-Electron Configurations and Orbital Diagrams

Magnetic mome...

Question

Magnetic moment of $F e^{3 +}$ ions $\sqrt{35}$ BM. Determine number of unpaired electrons.

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Solution

Magnetic moment $= \sqrt{n (n + 2)}$
where $n$ is no. of electrons.
$\sqrt{35} = \sqrt{n (n + 2)}$
$⟹ n = 5$ unpaired electrons.

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