Magnetic moment of $S c^{2 +}$ = Magnetic moment of $C u^{2 +}$
If true enter 1, else enter 0.

Open in App

Solution

As ${S c}^{2 +}$ and ${C u}^{2 +}$ has same number of unpaired electrons, i.e. 1 unpaired electron due to having $d^{1}$ and $d^{9}$ configurations respectively, they also have same magnetic moment.
Hence , the magnetic moment $= \sqrt{n (n + 2)}) = \sqrt{1 (1 + 2)} = \sqrt{3} = 1.73$ BM.
So, both have same magnetic moment equal to 1.73 BM.

Suggest Corrections

Similar questions

V^{2 +}

C o^{2 +}

[F e (C N)_{6}]^{3 -}

1.73 B M

[F e (H_{2} O)_{6}]^{3 +}

5.92 B M

[F e (H_{2} O)_{6}]^{2 +}

\sqrt{24} B M

\sqrt{15}

[F e (H_{2} O)_{5} N O]^{2 +}

O . N .

F e

F e

\sqrt{15} B . M .

Join BYJU'S Learning Program