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Byju's Answer
Standard IX
Chemistry
Quantum Number
Magnetic mome...
Question
Magnetic moment of V(Z = 23), Cr( Z = 24), and Mn(Z = 25) are x, y, z, respectively, hence:
A
x = y = z
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B
x < y < z
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C
x < z < y
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D
z < y < x
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Solution
The correct option is
C
x < z < y
As we know,
magnetic moment
μ
=
√
n
(
n
+
2
)
where n = no of unpaired electron
so higher the no of unpaired electron, higher is the magnetic moment.
V : 3 paired electrons x
Cr: 6 unpaired electrons y
Mn: 5 unpaired electrons z
We know that number of unpaired electron increases the magnetic moment also increases.
So,
y
>
z
>
x
Hence the correct option is C.
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0
Similar questions
Q.
Magnetic moments of
V
(
Z
=
23
)
,
C
r
(
Z
=
24
)
and
M
n
(
Z
=
25
)
are
x
,
y
,
z
. Hence
Q.
The magnetic moments of
C
r
(
Z
=
24
),
M
n
(
Z
=
25
) and
F
e
(
Z
=
26
) are
x
,
y
and
z
respectively. Hence,
Q.
Prove that
∣
∣ ∣ ∣
∣
y
z
−
x
2
z
x
−
y
2
x
y
−
z
2
z
x
−
y
2
x
y
−
z
2
y
z
−
x
2
x
y
−
z
2
y
z
−
x
2
z
x
−
y
2
∣
∣ ∣ ∣
∣
is divided by
(
x
+
y
+
z
)
and hence find the quotient.
Q.
Prove that
∣
∣ ∣ ∣
∣
y
z
−
x
2
z
x
−
y
2
x
y
−
z
2
z
x
−
y
2
x
y
−
z
2
y
z
−
x
2
x
y
−
z
2
y
z
−
x
2
z
x
−
y
2
∣
∣ ∣ ∣
∣
is divisible by
(
x
+
y
+
z
)
and hence find the quotient
Q.
Magnetic moments of
C
r
(
Z
=
24
)
,
M
n
(
Z
=
25
)
and
F
e
(
Z
=
26
)
, are
x
,
y
,
z
.
They are in order:
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