Question

Magnetic moment of $x^{n+}$ is $\sqrt{24}$ B.M. Hence No. of unpaired electron and value of '$n$' respectively. (Atomic number = 26)

• A. 4, 3
• B. 3, 5
• C. 4, 2
• D. 4, 1

Answer 1

Answer: (C)

4, 2

Option (B) is correct.
Magnetic moment of $x^{n+}$ is $\sqrt{24}$ B.M. Hence No. of unpaired electron and value of 'n' are 4,2 respectively.
$\sqrt{24}$ =$\sqrt{n(n+2)}$
$24=n(n+2)$
$n^2+2n-24=0$
$n=-6$ or $n=+4$