Magnetite, a magnetic oxide of iron used on recording tapes, crystallises with iron atoms occupyin 1/8 of the tetrahedral holes and 1/2 of the octahedral holes in a closed packed array of oxides ions. What is the formula of magnetite?

Open in App

Solution

$↗ (4)_{↘ O h \Rightarrow F e 1 / 2 \times 4 = 2}^{↗ F e \Rightarrow 1 / 8 \times 8 = 1}$
ccp lettice $\frac{1}{2} \times 4 = 2$ $^{\circ} n voids = 4$

Td " = 8
Total Fe = 3
Formula = $F e_{3} O_{4}$

Suggest Corrections

Similar questions

Q. Zinc sulphide crystallises with zinc ions occupying half of the tetrahedral holes in a closed packed array of sulphide ions. What is the formula of zinc sulphide?

Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.

Q. Aluminium oxide crystallizes with aluminium ions in 2/3 of the line octahedral and 1/3 octahedral holes remaining vacant in a closest packed array of oxide ions. What is the formula of aluminium oxide?

Q. If the unit cell of a mineral has cubic closed packed (ccp) array of oxygen atoms with

^{'} m^{'}

fraction of octahedral holes occupied by aluminium ions and

^{'} n^{'}

fraction of tetrahedral holes occupied by magnesium ions;

m

and

n

respectively, are:

If unit cell of a mineral has cubic closed packed array of oxygen atoms with m fraction of octahedral holes occupied by aluminium ion and n fraction of tetrahedral holes occupied by magnesium ions, m and n, respectively are

Join BYJU'S Learning Program

Magnetite, a magnetic oxide of iron used on recording tapes, crystallises with iron atoms occupyin 1/8 of the tetrahedral holes and 1/2 of the octahedral holes in a closed packed array of oxides ions. What is the formula of magnetite?

↗(4)↗Fe⇒1/8×8=1↘Oh⇒Fe1/2×4=2ccp lettice 12×4=2 ∘nvoids=4 Td " = 8 Total Fe = 3Formula = Fe3O4

$↗ (4)_{↘ O h \Rightarrow F e 1 / 2 \times 4 = 2}^{↗ F e \Rightarrow 1 / 8 \times 8 = 1}$
ccp lettice $\frac{1}{2} \times 4 = 2$ $^{\circ} n voids = 4$

Td " = 8
Total Fe = 3
Formula = $F e_{3} O_{4}$