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Telescopes

Magnifying po...

Question

Magnifying power for relaxed eye in case of telescope is 9 and length of telescope is $40 c m$ , then find focal length of eyepiece.

A

f_{e} = 36 c m

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B

f_{e} = 4 c m

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C

f_{e} = 24 c m

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D

f_{e} = 31 c m

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Solution

The correct option is B $f_{e} = 4 c m$
$∵ m = \frac{f_{0}}{f_{e}} = 9$
$and L = f_{0} + f_{e} = 40$
$\Rightarrow 9 f_{e} + f_{e} = 40$
$\Rightarrow f_{e} = 4$

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