Magnitude of resultant of 3 vectors −−→OA,−−→OB, and −−→OC as shown below is
A
r
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B
2r
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C
r(1+√2)
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D
r(√2−1)
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Solution
The correct option is Cr(1+√2) −−→OA and −−→OC are equal in magnitude and inclined to each other at an angle 90°. So their resultant is √2r, and it acts along −−→OB. So, Resultant =r+√2r =r(1+√2)