Magnitude of torque of →F=2^i−^j−^k acting at (−5,2,1) about the origin is :
Magnitude of force
F=√(2)2+(−1)2+(−1)2
F=√6N
Distance of the point (−5,2,1) from origin is given by
r=√(−5−0)2+(2−0)2+(1−0)2
r=√30m
Now torque is
τ=F×r
τ=√30×6
τ=13.42Nm