The correct option is C Saturday
2nd Oct 1869 = 1868 years + Period from 01/01/1869 to 02/10/1869
1600 years have 0 odd days.
200 years have 3 odd days.
Now, 68 years comprise of 17 leap years and 51 ordinary years.
So, the number of odd days in 68 years=17×2+51=85=12 weeks, 1 odd day.
Thus, 1868 years have 0 + 3 + 1 = 4 odd days.
In 1869, till 2nd Oct, the number of odd days is calculated as follows:
Month Jan Feb Mar Apr May Jun July Aug Sept Oct
Days 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 2 = 275 days or 39 weeks and 2 odd days
So, total number of odd days = 0 + 3 + 1 + 2 = 6 odd days.
Hence, the day on 2nd Oct 1869 is Saturday.