Question

Mahesh sold two cell phones at $Rs.9900$ each. On one he gained $10\%$ and on the other he lost $10\%$. Find
a) the cost price of each cell phone.
b) the total profit or loss in the whole transaction
c) his total profit or loss $\%$

Answer 1

Given selling price (S.P)of each phone $=Rs.9900$ and $10\%$ loss and $10\%$ gain on two phones.

(i) Let the C.P of each cell phone be $x$.
Since, $10\%$ profit.
So, $x\times \frac{110}{100}=S.P$

$\Rightarrow x=\frac{10}{11}\times S.P$
$=\frac{10}{11}\times 9900$
$=10\times 900$
$=Rs.9000$

Therefore, the C.P of cell phone is $=Rs.9000$ when he gets profit.
Thus, profit amount $=9900-9000=Rs.900$

Similar way, the cost price of loss yielding phone $=\frac{10}{9}\times S.P$
$=\frac{10}{9}\times 9900$

$=10\times 1100$
$=Rs.11000$
The cost price of cell phone is $Rs.1100$, when he gets loss.
Thus, the loss amount $=11000-9900=Rs.1100$

(ii) Since, loss amount $>$ profitable amount.
So, Net loss $=1100-900=Rs.200$

(iii) Since, Loss ($\%$)$=\frac{\text{loss}}{C.P}\times 100$
$=\frac{200}{20000}\times 100$ [where $C.P=9000+11000=Rs.20000$]

$=1\%$
Hence, total loss($\%$)$=1\%$