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Nitration of Aromatics

Main reason f...

Question

Main reason for brown ring test of $N O_{3}^{-}$ is?

Negligible tendency of

F e S O_{4}

to form complex.

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Reducing power of

F e S O_{4}

to convert

N O_{3}^{-}

to NO

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Decomposition of

F e S O_{4}

to give

S O_{2}

gas

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Oxidising property of

F e S O_{4}

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Solution

The correct option is B Reducing power of $F e S O_{4}$ to convert $N O_{3}^{-}$ to NO
Reducing power of $F e S O_{4}$ to convert $N O_{3}^{-}$ to $N O$

Suggest Corrections

Similar questions

The brown ring in the detection of $N O_{3}^{-}$ ion is due to the formation of

F e S O_{4}

[F e (H_{2} O)_{5} N O]^{2 +}

F e S O_{4}

N O_{3}^{-}

c o n c . H_{2} S O_{4}

F e S O_{4}

F e {S O}_{4}

F e {S O}_{4}

{N O}_{2}^{-}

{N O}_{3}^{-}

H_{2} {S O}_{4}

(I)

(I I)

N O

(I I I)

{F e}_{2} {({S O}_{4})}_{3}

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