Major product for given reaction:
$M e - C l + N H_{3}$ (excess) $⟶$ ?

M e N H_{2}

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M e_{2} N H

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M e_{3} N

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All of the above

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Solution

The correct option is A $M e N H_{2}$
Since only one mole of methyl chloride has been taken so no further reaction will take place.
$M e - C l + N H_{3 (e x c e s s)} \to M e N H_{2}$

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M e - C l + N H_{3}

⟶

{C H}_{3} - C l + A g C N \to P r o d u c t .

P h - C l + B r_{2} Anhydrous F e B r_{3} - ---------- \to

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