Major product of the reaction is:
$H_{2} C = C H - C H_{2} - I H I (e x c e s s) - ------ \to C C l_{4}$

C H_{3} - C H | I - C H_{2} | I

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C H_{3} - C H | I - C H_{3}

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C H_{3} - C H_{2} - C H_{2} - I

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I - C H_{2} - C d H_{2} - C H_{2} - I

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Solution

The correct option is B $C H_{3} - C H | I - C H_{3}$
Refer to image 01
First addition results in di-iodide but highly unstable so it escapes out fast thereby, (refer to image 02) is the final product.

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Similar questions

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

(A) C H_{3} - C H_{2} - C | B r H - + C H - C H_{3}

(B) C H_{3} - C H_{2} - C | I H - + C H - C H_{3}

C H_{3} - C H_{2} - C H_{2} - O H

H C O O H

C H_{3} - C H_{2} - C H = C H_{2}

R - C H_{2} - O H C u - -- \to 573 K . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

C H_{3} - C H = C H_{2} + H_{2} O^{+} . . . . . . . . . . . . . . . . . . . . . . . . . . .

A g N O_{3}

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