Major product [X] will be:

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Solution

The correct option is D
This is Baeyer Villiger oxidation.
In this reaction, the aldehyde is oxidised to carboxylic acid and the ketone is oxidised to ester group.
In this reaction, the oxygen from peroxy acid is getting inserted between the carbonyl group and H of an aldehyde and the 'R' of ketone.
If it is a unsymmetrical ketone, then, ‘O’ insertion occurs between the carbonyl group and the R group which have higher migratory aptitude.
The order of migratory aptitude in Baeyer villiger oxidation is
$H > 3^{o} > 2^{o} > P h > 1^{o} > C H_{3}$
Since, secondary alkyl group has more migratory aptitude than phenyl, the 'O' from peroxy acid insert between carbonyl and secondary alkyl group.

Hence, option (b) is correct.

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