Make g the subject of formula - mv2-r - T - mg-Hence find g- if m - 1-2- v - 4- r - 2 and T - 2-4

The correct option is A g=6 mv^2/r= T+mg Or #160; mv^2= Tr+mgr Or #160; mv^2 Tr= mgr Or #160; g= mv^2 Trmr given the values m=1 ...

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Standard XII

Physics

Introduction to Radial & Tangential Acceleration

Make g the su...

Question

Make g the subject of formula : $\frac{m v^{2}}{r} = T + m g$ .
Hence find g, if $m = 1.2, v = 4, r = 2$ and $T = 2.4$

g = 6

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g = 9.8

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g = 10

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None of these

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Solution

The correct option is A $g = 6$
$\frac{m v^{2}}{r} = T + m g$

Or $m v^{2} = T r + m g r$
Or $m v^{2} - T r = m g r$
Or $g = \frac{m v^{2} - T r}{m r}$
given the values m=1.2 ,v=4 ,r=2 and T=2.4
$g = \frac{2 \times 4^{2} - 2.4 \times 2}{1.2 \times 2} = \frac{19.2 - 4.8}{2.4} = \frac{14.4}{2.4} = 6$

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Make g the subject of formula : mv2r=T+mg.Hence find g, if m=1.2,v=4,r=2 and T=2.4

The correct option is A g=6mv2r=T+mgOr mv2=Tr+mgrOr mv2−Tr=mgrOr g=mv2−Trmrgiven the values m=1.2 ,v=4 ,r=2 and T=2.4g=2×42−2.4×21.2×2=19.2−4.82.4=14.42.4=6

Make g the subject of formula : $\frac{m v^{2}}{r} = T + m g$ .
Hence find g, if $m = 1.2, v = 4, r = 2$ and $T = 2.4$

The correct option is A $g = 6$
$\frac{m v^{2}}{r} = T + m g$

Or $m v^{2} = T r + m g r$
Or $m v^{2} - T r = m g r$
Or $g = \frac{m v^{2} - T r}{m r}$
given the values m=1.2 ,v=4 ,r=2 and T=2.4
$g = \frac{2 \times 4^{2} - 2.4 \times 2}{1.2 \times 2} = \frac{19.2 - 4.8}{2.4} = \frac{14.4}{2.4} = 6$