Make 'm' the subject of formula.

m = \frac{2 E}{v^{2} - 2 g h}

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m = \frac{2 E}{v^{2} + 2 g h}

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m = \frac{4 E}{v^{2} + 2 g h}

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none of the above

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Solution

The correct option is B $m = \frac{2 E}{v^{2} + 2 g h}$
Given, $E = \frac{1}{2} m v^{2} + m g h$
$\Rightarrow E = \frac{1}{2} (m v^{2} + 2 m g h)$
$\Rightarrow 2 E = m v^{2} + 2 m g h$
$\Rightarrow 2 E = m (v^{2} + 2 g h)$
$\Rightarrow m = \frac{2 E}{v^{2} + 2 g h}$

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