Question

Make M the subject of formula
$T=2\pi \sqrt{\frac{1}{MH}}$

• A. $M=\frac{2{\pi }^2}{T^{2}H}$
• B. $M=\frac{4{\pi }^2}{T^{2}H}$
• C. $M=\frac{8{\pi }^2}{T^{2}H}$
• D. $M=\frac{16{\pi }^2}{T^{2}H}$

Answer 1

The correct option is B $M=\frac{4{\pi }^2}{T^{2}H}$

Given, $T=2\pi \sqrt{\frac{1}{MH}}$
$\Rightarrow \frac{T}{2\pi }=\sqrt{\frac{1}{MH}}$
Squaring both sides,
$\Rightarrow \frac{T^2}{4{\pi }^2}=\frac{1}{MH}$
$\Rightarrow M=\frac{4{\pi }^2}{T^{2}H}$