Question

Making use of the cube root table, find the cube root
5112

Answer 1

By prime factorisation, we have:

$5112=2^3\times 3^2\times 71\Rightarrow \sqrt[3]{5112}=2\times \sqrt[3]{9}\times \sqrt[3]{71}$

By the cube root table, we have:

$\sqrt[3]{9}=2.080and\sqrt[3]{71}=4.141$

$\therefore$ $\sqrt[3]{5112}=2\times \sqrt[3]{9}\times \sqrt[3]{71}=2\times 2.080\times 4.141=17.227$ (upto three decimal places)

Thus, the required cube root is 17.227.