Question

Making use of the cube root table, find the cube root
732

Answer 1

We have:

$730<732<740\Rightarrow \sqrt[3]{730}<\sqrt[3]{732}<\sqrt[3]{740}$

From cube root table, we have:

$\sqrt[3]{730}=9.004\text{and}\sqrt[3]{740}=9.045$

For the difference (740$-$730), i.e., 10, the difference in values

$=9.045-9.004=0.041$

$\therefore$ For the difference of (732$-$730), i.e., 2, the difference in values

$=\frac{0.041}{10}\times 2=0.0082$

$\therefore$ $\sqrt[3]{732}=9.004+0.008=9.012$