Question

Making use of the cube root table, find the cube root
7342

Answer 1

We have:

$7300<7342<7400\Rightarrow \sqrt[3]{7000}<\sqrt[3]{7342}<\sqrt[3]{7400}$

From the cube root table, we have:

$\sqrt[3]{7300}=19.39\text{and}\sqrt[3]{7400}=19.48$

For the difference (7400$-$7300), i.e., 100, the difference in values

$=19.48-19.39=0.09$

$\therefore$ For the difference of (7342$-$7300), i.e., 42, the difference in the values

$=\frac{0.09}{100}\times 42=0.0378=0.037$

$\therefore$ $\sqrt[3]{7342}=19.39+0.037=19.427$