Question

Making use of the cube root table, find the cube root
7532

Answer 1

We have:

$7500<7532<7600\Rightarrow \sqrt[3]{7500}<\sqrt[3]{7532}<\sqrt[3]{7600}$

From the cube root table, we have:

$\sqrt[3]{7500}=19.57\text{and}\sqrt[3]{7600}=19.66$

For the difference (7600$-$7500), i.e., 100, the difference in values

$=19.66-19.57=0.09$

$\therefore$ For the difference of (7532$-$7500), i.e., 32, the difference in values

$=\frac{0.09}{100}\times 32=0.0288=0.029$ (up to three decimal places)

$\therefore$ $\sqrt[3]{7532}=19.57+0.029=19.599$