Question

Making use of the cube root table, find the cube root
833

Answer 1

We have:

$830<833<840\Rightarrow \sqrt[3]{830}<\sqrt[3]{833}<\sqrt[3]{840}$

From the cube root table, we have:

$\sqrt[3]{830}=9.398\text{and}\sqrt[3]{840}=9.435$

For the difference (840$-$830), i.e., 10, the difference in values

$=9.435-9.398=0.037$

$\therefore$ For the difference (833$-$830), i.e., 3, the difference in values

$=\frac{0.037}{10}\times 3=0.0111=0.011$ (upto three decimal places)

$\therefore$ $\sqrt[3]{833}=9.398+0.011=9.409$