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Question

Man A is sitting in a car moving with a speed of 54 km/hr observes a man B in front of the car crossing perpendicularly a road of width 15 m in three seconds. Then the velocity of man B (in m/s) will be

A
510 towards the car at some angle
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B
510 away from the car at some angle
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C
5 perpendicular to the road
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D
15 along the road
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Solution

The correct option is B 510 away from the car at some angle
Velocity of A 54km/hr15m/s.
Since the motion of B is seen in perpendicular direction by A.
Its component of velocity will be 15 m/s in the direction of motion of A in same direction. Now Its velocity is 5 m/s in perpendicular direction .
Magnitude of velocity 52+152250510m/s at some angle away from the car.
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