Question

Man of weight $40$ kg standing on boat of weight $15kg$ and length $2m$ man walk one end to other what will be displacement of boat

Answer 1

Given,

The weight of the man is $40kg$ and weight of the boat is $15kg,$

length $=2m$

Since the center of mass remain unchanged,

Thus, the mass of the man is multiplied displacement is equal to the product of the mass of the boat with the displacement of the boat,

Displacement of man $=2-x$

So, $40\times (2-x)=15\times x$

$\Rightarrow x=\frac{80}{55}=1.45m$

where x is the displacement of the boat.