Manganese (IV) oxide, lead (IV) oxide and red lead $[P b_{3} O_{4}]$ react with conc. $H C I$ liberating chlorine.Write the equation for the reaction of conc. $H C l$ with $P b_{3} O_{4}$ .

{2 P b}_{3} O_{4} + 2 H C l \to 6 P b C l + H_{2} O + {5 C l}_{2}

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{2 P b}_{3} O_{4} + 16 H C l \to 6 P b C l + {8 H}_{2} O + {5 C l}_{2}

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{2 P b}_{3} O_{4} + 6 H C l \to 2 P b C l + {8 H}_{2} O + {5 C l}_{2}

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{P b}_{3} O_{4} + 16 H C l \to 3 P b C l + {8 H}_{2} O + {5 C l}_{2}

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Solution

The correct option is B ${2 P b}_{3} O_{4} + 16 H C l \to 6 P b C l + {8 H}_{2} O + {5 C l}_{2}$
${2 P b}_{3} O_{4} + 16 H C l \to 6 P b C l + {8 H}_{2} O + {5 C l}_{2}$

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Similar questions

Q. In the following reaction:

2 K M n O_{4} + 16 H C l \to 5 C l_{2} + 2 M n C l_{2} + 2 K C l + 8 H_{2} O

, the reduction product is :

Q. Manganese (IV) oxide, lead (IV) oxide and red lead

[P b_{3} O_{4}]

react with conc.

H C I

liberating chlorine. What is the common property being shown by these metal oxides.

Manganese (IV) oxide, lead (IV) oxide and red lead (Pb₃O₄) react with concentrated hydrochloric acid to liberate chlorine.
(a) Name the common property exhibited by these metal oxides.
(b) Write the equation for the reaction of concentrated hydrochloric acid with Pb₃O₄.

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K M n O_{4} + H_{2} S O_{4} + H C l \to K_{2} S O_{4} + M n S O_{4} + C l_{2} + H_{2} O

Q. Identify the oxidant and the reductant in the following reaction respectively:

2 K M n O_{4} + 10 K C l + 8 H_{2} S O_{4} \to 2 M n S O_{4} + 6 K_{2} S O_{4} + 8 H_{2} O + 5 C l_{2}

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Manganese (IV) oxide, lead (IV) oxide and red lead [Pb3O4] react with conc. HCI liberating chlorine.Write the equation for the reaction of conc. HCl with Pb3O4.

The correct option is B 2Pb3O4+16HCl→6PbCl+8H2O+5Cl22Pb3O4+16HCl→6PbCl+8H2O+5Cl2

Manganese (IV) oxide, lead (IV) oxide and red lead $[P b_{3} O_{4}]$ react with conc. $H C I$ liberating chlorine.Write the equation for the reaction of conc. $H C l$ with $P b_{3} O_{4}$ .

The correct option is B ${2 P b}_{3} O_{4} + 16 H C l \to 6 P b C l + {8 H}_{2} O + {5 C l}_{2}$
${2 P b}_{3} O_{4} + 16 H C l \to 6 P b C l + {8 H}_{2} O + {5 C l}_{2}$