manju 's age is three years older than sunitha's age.6 years ago manju was four times sunitha's age. find their present age

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Solution

$Let the present age of Sunita = x yrs Then present age of Manju = (x + 3) yrs 6 YEARS AGO : Sunita' s age = (x - 6) yrs Manju' s age = (x - 3) yrs Now, (x - 3) = 4 (x - 6) \Rightarrow x - 3 = 4 x - 24 \Rightarrow x - 4 x = - 24 + 3 \Rightarrow - 3 x = - 21 \Rightarrow x = \frac{21}{3} = 7 So, Sunita' s present age = 7 yrs Manju' s present age = 10 yrs$

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manju 's age is three years older than sunitha's age.6 years ago manju was four times sunitha's age. find their present age

Let the present age of Sunita = x yrsThen present age of Manju = x+3 yrs6 YEARS AGO :Sunita's age = x-6 yrsManju's age = x - 3 yrsNow,x-3 = 4x-6⇒x-3 = 4x - 24⇒x - 4x = -24 + 3⇒-3x = -21⇒x = 213 = 7So, Sunita's present age = 7 yrsManju's present age = 10 yrs