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Question

Manuel ate 13 of the cracker on a plate.

His brother ate 14 of the cracker.

There were 5 crackers left on the plate.

How many cracker were there to begin with?


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Solution

Finding the number of crackers:

Given,

Manuel ate 13 of the cracker on a plate

His brother ate 14 of the cracker

Remaining crackers were 5

Let the total number of crackers on the plate be x

Then, Manuel ate x3 crackers on the plate.

His brother then ate, x-x34 crackers and after that 5 crackers were left on the plate.

We can frame an equation for the remaining crackers as,

x-x3+2x34=5x-x3+x6=5x-x2=5x=10

Hence, in the beginning, there were 10 crackers on the plate.


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