Manukaka distribute $96$ marbles among the children of a class in such a way that each child got equal number of marble. In the same class, sameway he also distributed $72$ chocolates. No chocolate and marble is left. How many maximum students are there in this class so that it is possible?

22

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24

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Solution

The correct option is D $24$
Factorization of the following.
Maximum students are $= 24$
$72 = (1, 2, 3, 4, 6, 8, 9, 12, 72)$
$24 = (1, 2, 3, 4, 6, 8, 12, 24)$
Since, The common factor is $1, 2, 3, 4$
$H . C . F = 24$
Hence, The correct option is $B$

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Manukaka distribute 96 marbles among the children of a class in such a way that each child got equal number of marble. In the same class, sameway he also distributed 72 chocolates. No chocolate and marble is left. How many maximum students are there in this class so that it is possible?

The correct option is D 24Factorization of the following.Maximum students are =2472=(1,2,3,4,6,8,9,12,72)24=(1,2,3,4,6,8,12,24)Since, The common factor is 1,2,3,4H.C.F=24Hence, The correct option is B

Manukaka distribute $96$ marbles among the children of a class in such a way that each child got equal number of marble. In the same class, sameway he also distributed $72$ chocolates. No chocolate and marble is left. How many maximum students are there in this class so that it is possible?

The correct option is D $24$
Factorization of the following.
Maximum students are $= 24$
$72 = (1, 2, 3, 4, 6, 8, 9, 12, 72)$
$24 = (1, 2, 3, 4, 6, 8, 12, 24)$
Since, The common factor is $1, 2, 3, 4$
$H . C . F = 24$
Hence, The correct option is $B$