Many ROCs of are possible, ROC for which the given sequence is a casual sequence is $X (z) = \frac{z (z - 4)}{(z - 1) (z - 2) (z - 3)}$ $| z | > a$ where $a$ is

3

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Solution

The correct option is A 3
As for a casual sequence , ROC lies outside the outermost pole.

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