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Question

Manya has three times as many sweets a Puja. If manya gives eight sweets to puja, they both will have the same number of sweet. How many sweet does each of them have?

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Solution

let no of sweets Puja has =x

no. of sweets Manya has =3x

when Manya gives 8 sweets to Puja , then

No. of sweets Puja has =x+8

No. of sweets Manya has =3x8

according to problem ; x+8=3x8

16=3xx

16=2x

8=x

no. of sweets Puja has =8

No. of sweets Manya has =3×8=24

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