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In a hydro power plant, stored water falls from a height of 100 m at the rate of 3000 kg per second. 1)calculate the initial potential energy of this water. 2)what is the kinetic energy of water that rotates the turbine of power station. 3)if only 50% of kinetic energy of water is utilised to produce energy calculate the electrical power generated.
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Solution

DearStudent
$P o t e n t i a l e n e r g y = M g h = 3000 \times 10 \times 100 = 3 \times 10^{6} J W h e n i t f a l l s o n t u r b i n e w h o l e o f p o t e n t i a l e n e r g y i s c h a n g e d t o k i n e t i c e n e r g y b y t h e c o n s e r v a t i o n o f e n e r g y . 3) E n e r g y = 0.5 * 3 \times 10^{6} = 1.5 \times 10^{6} J P o w e r = E n e r g y * t i m e a s t i m e i s 1 s e c p o w e r = 1.5 \times 10^{6} W a t t R E G A R D S$

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DearStudent Potential energy=Mgh=3000×10×100=3×106JWhen it falls on turbine whole of potential energy is changed to kinetic energy by the conservation of energy.3) Energy=0.5*3×106=1.5×106JPower=Energy*timeas time is 1secpower=1.5×106WattREGARDS