Question

Marie and Lily were given the same mass of pizza dough.Marie use the dough to make 8 large pizza and had 540g of dough left.Lily used the dough to make 18 small pizzas and had 60g of dough left. The mass of dough used for 2 large pizzas was the same as that for 3 small pizzas. What is the maximum number of pizzas that can be made with the remaining dough from both girls ?

Answer 1

$$\begin{gathered} \mathrm{Assuming}\mathrm{your}\mathrm{question}\mathrm{as} \\ \mathrm{What}\mathrm{is}\mathrm{the}\mathrm{maximum}\mathrm{number}\mathrm{of}\mathrm{small}\mathrm{pizzas}\mathrm{that}\mathrm{can}\mathrm{be}\mathrm{made}\mathrm{with}\mathrm{the}\mathrm{remaining}\mathrm{dough}\mathrm{from}\mathrm{both}\mathrm{girls}? \\ \mathrm{Dough}\mathrm{Marie}\mathrm{has}=8\mathrm{large}\mathrm{pizza}\text{'}\mathrm{s}+540\mathrm{g} \\ \mathrm{Dough}\mathrm{Lily}\mathrm{has}=18\mathrm{small}\mathrm{pizza}\text{'}\mathrm{s}+60\mathrm{g} \\ \mathrm{Also},\mathrm{Dough}\mathrm{used}\mathrm{for}2\mathrm{large}\mathrm{pizza}\text{'}\mathrm{s}=\mathrm{Dough}\mathrm{used}\mathrm{for}3\mathrm{small}\mathrm{pizza}\text{'}\mathrm{s} \\ \Rightarrow \mathrm{Dough}\mathrm{used}\mathrm{for}1\mathrm{large}\mathrm{pizza}=\mathrm{Dough}\mathrm{used}\mathrm{for}\frac{3}{2}\mathrm{small}\mathrm{pizza}\text{'}\mathrm{s} \\ \Rightarrow \mathrm{Dough}\mathrm{used}\mathrm{for}8\mathrm{large}\mathrm{pizza}\text{'}\mathrm{s}=\mathrm{Dough}\mathrm{used}\mathrm{for}12\left(=\frac{3}{2}\times 8\right)\mathrm{small}\mathrm{pizza}\text{'}\mathrm{s} \\ \mathrm{So},\mathrm{Dough}\mathrm{Marie}\mathrm{has}=12\mathrm{small}\mathrm{pizza}\text{'}\mathrm{s}+540\mathrm{g} \\ \mathrm{Dough}\mathrm{used}\mathrm{for}1\mathrm{small}\mathrm{pizza}=\frac{540-60}{18-12}=\frac{480}{6}=80 \\ \mathrm{So},\mathrm{no}.\mathrm{of}\mathrm{small}\mathrm{pizza}\text{'}\mathrm{s}\mathrm{that}\mathrm{can}\mathrm{be}\mathrm{made}\mathrm{from}540\mathrm{g}\mathrm{and}60\mathrm{g}\mathrm{dough}=\frac{540+60}{80}=\frac{600}{80}=7.5=7\left(\mathrm{approx}\right) \end{gathered}$$