Question

Mark (✓) against the correct answer
$\frac{-102}{119}$ in standard form is

(a) $\frac{-4}{7}$
(b) $\frac{-6}{7}$
(c) $\frac{-6}{17}$
(d) none of these

Answer 1

$\begin{array}{l}\\ \left(\text{b}\right)\frac{-6}{7}\end{array}$



$\begin{array}{l}\mathrm{H}.\mathrm{C}.\mathrm{F}.\mathrm{of}102\mathrm{and}119\mathrm{is}17\\ \begin{array}{l}\frac{-102÷17}{119÷17}=\frac{-6}{7}\\ \begin{array}{l}\text{The standard form of}\frac{-102}{119}\text{is}\frac{-6}{7}\\ \end{array}\end{array}\end{array}$