Question

Mark (✓) against the correct answer
${\left(\frac{-3}{2}\right)}^{-1}=?$

(a) $\frac{2}{3}$
(b) $\frac{-2}{3}$
(c) $\frac{3}{2}$
(d) none of these

Answer 1

(b) $\frac{-2}{3}$
We have:
${\left(\frac{-3}{2}\right)}^{-1}={\left(\frac{2}{-3}\right)}^1$ $\left[s\mathrm{ince}{\left(\frac{a}{b}\right)}^{-n}={\left(\frac{b}{a}\right)}^n\right]$
= $\frac{-2}{3}$