Question

Mark (✓) against the correct answer
Each side of an equilateral triangle is 8 cm. Its area is

(a) $16\sqrt{3}{\mathrm{cm}}^2$
(b) $32\sqrt{3}{\mathrm{cm}}^2$
(c) $24\sqrt{3}{\mathrm{cm}}^2$
(d) $8\sqrt{3}{\mathrm{cm}}^2$

Answer 1

(a) $16\sqrt{3}{\mathrm{cm}}^2$

Given that each side of an equilateral triangle is 8 cm.
∴ Area of the equilateral triangle = $\frac{\sqrt{3}}{4}{\left(\mathrm{side}\right)}^2$ sq. units

= $\frac{\sqrt{3}}{4}{\left(8\right)}^2$ cm²

= $\left(\frac{\sqrt{3}}{4}\times 64\right)$ cm² = $16\sqrt{3}$ cm²