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Question

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In a ∆ABC, if ∠A + ∠B = 65° and ∠B +∠C = 140°. Then, = ∠B?

(a) 25°
(b) 35°
(c) 40°
(d) 45°

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Solution

(a) 25°Given:A+B=65°A=65°-B ...(i)B+C=140°C=140°-B ...(ii)In ABC:A+B+C=180°Putting the value of B and C:65°-B+B+140°-B=180°-B=180°-205°B=25°

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