Question

Mark (✓) against the correct answer in each of the following:
$\frac{1}{(\sqrt{18}-\sqrt{32})}=?$
(a) $\sqrt{2}$
(b) $\frac{1}{\sqrt{2}}$
(c) $-\sqrt{2}$
(d) $\frac{-1}{\sqrt{2}}$

Answer 1

(d) $\frac{-1}{\sqrt{2}}$

$$\begin{gathered} \frac{1}{\sqrt{18}-\sqrt{32}} \\ =\frac{1}{3\sqrt{2}-4\sqrt{2}} \\ =\frac{1}{-\sqrt{2}}=\frac{-1}{\sqrt{2}} \end{gathered}$$