Question

Mark (✓) against the correct answer
In the given figure, AOB is a straight line, ∠AOC = 68° and ∠BOC = x°.
The value of x is



(a) 32
(b) 22
(c) 112
(d) 132

Answer 1

$$\begin{gathered} \left(\mathrm{x}\right)112 \\ \angle AOC+\angle AOB=180°(\mathrm{linear}\mathrm{pair}) \\ 68°+\mathrm{x}°=180° \\ \Rightarrow x°=180°-68° \\ \Rightarrow x°=112° \end{gathered}$$